NBA teams are allowed to negotiate with free agents beginning July 1, but can’t sign them to official contracts until July 8, allowing the league to review its revenue and set the salary cap in a period of time known as the July Moratorium. Although not its intended purpose, it also allows for a free agent who agreed to terms with a team to change his mind and sign elsewhere.
Star center DeAndre Jordan, who played for the Los Angeles Clippers last season, verbally agreed to terms with the Dallas Mavericks, but had a change of heart and re-signed with the Clippers to a four-year max deal worth $88 million just minutes after the signing period began.
Recruiting Jordan to return to the Clippers were the Brand Jordan-sponsored Chris Paul and Blake Griffin, teammates of the center while in Los Angeles. While Paul and Griffin are established superstars in the league, Jordan’s recent play has caused his stock to rise.
But will his rising stock result in a signature shoe?
Jordan has had sponsorships with brands in the past, wearing Under Armour as an athlete endorsed by the Baltimore-based brand before jumping ship at the end of the contract to Nike. Throughout the 2014-15 season, he mostly wore the Nike Zoom LeBron Soldier VIII, although he was also spotted wearing the Nike Hyperdunk 2014.
But not every star gets a signature shoe.
Guards and forwards, the players that often bring a flashy element to the court, are typically the players to get signature shoes from brands, most notably with Under Armour with guard Stephen Curry and the Curry One and Nike with forward LeBron James and the LeBron 12. Signature shoes happen far less often – and aren’t nearly as popular – for centers. Dwight Howard, center for the Houston Rockets, recently had a signature shoe with Adidas. Howard’s shoe was promoted far less by the brand than the shoes of guards John Wall and Damian Lillard.
While it remains to be seen if Jordan will be wearing a signature shoe next season, one thing is for sure: he will be wearing it while in a Clippers uniform.